Here are the answers to the maths questions set by Batemans supporter Chris Glover.
1. 15 By trial and error or by solving 3(x-10) = x
2. 29, 47 From 3rd term on, next term is sum of previous 2 (a Fibonacci sequence)
3. 400 By squaring and subtracting
OR the short way, difference of 2 squares (101 + 99) (101 – 99) = 200 x 2
4. 6 By listing 357, 375, 537, 573, 735,753
OR 3 ways of choosing 1st digit 2 for the 2nd and 1 for the third so 3 x 2 x 1 = 6
5. 24 Similar to 2nd way in Q4, but 4 digits so 4 x 3 x 2 x 1 = 24
6. 256 As repetition allowed, 4 ways of choosing each digit so 4 x 4 x 4 x 4 = 256
7. An equilateral triangle, (½ a point for triangle)
8. 6
